Base | Representation |
---|---|
bin | 100001101000011110111… |
… | …000001100100010000001 |
3 | 22011221122020012220100122 |
4 | 201220132320030202001 |
5 | 300331324333444441 |
6 | 4525431101030025 |
7 | 325656643465253 |
oct | 41503670144201 |
9 | 8157566186318 |
10 | 2311210453121 |
11 | 8111a7058479 |
12 | 313b17855315 |
13 | 139c3ba9479b |
14 | 7dc12805cd3 |
15 | 401be94c34b |
hex | 21a1ee0c881 |
2311210453121 has 2 divisors, whose sum is σ = 2311210453122. Its totient is φ = 2311210453120.
The previous prime is 2311210453091. The next prime is 2311210453127. The reversal of 2311210453121 is 1213540121132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2300742912400 + 10467540721 = 1516820^2 + 102311^2 .
It is a cyclic number.
It is not a de Polignac number, because 2311210453121 - 234 = 2294030583937 is a prime.
It is not a weakly prime, because it can be changed into another prime (2311210453127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155605226560 + 1155605226561.
It is an arithmetic number, because the mean of its divisors is an integer number (1155605226561).
Almost surely, 22311210453121 is an apocalyptic number.
It is an amenable number.
2311210453121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311210453121 is an equidigital number, since it uses as much as digits as its factorization.
2311210453121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 2311210453121 its reverse (1213540121132), we get a palindrome (3524750574253).
The spelling of 2311210453121 in words is "two trillion, three hundred eleven billion, two hundred ten million, four hundred fifty-three thousand, one hundred twenty-one".
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