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23113254431257 is a prime number
BaseRepresentation
bin1010100000101011110010…
…10100011110101000011001
310000211121100102220222212221
411100111321110132220121
511012141421113300012
6121054025453104041
74603606664041144
oct520257124365031
9100747312828787
1023113254431257
117401304624231
122713606188021
13cb87556296b3
1459c98a65105b
152a1367273507
hex15057951ea19

23113254431257 has 2 divisors, whose sum is σ = 23113254431258. Its totient is φ = 23113254431256.

The previous prime is 23113254431233. The next prime is 23113254431279. The reversal of 23113254431257 is 75213445231132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14538541947136 + 8574712484121 = 3812944^2 + 2928261^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23113254431257 is a prime.

It is not a weakly prime, because it can be changed into another prime (23113254431227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556627215628 + 11556627215629.

It is an arithmetic number, because the mean of its divisors is an integer number (11556627215629).

Almost surely, 223113254431257 is an apocalyptic number.

It is an amenable number.

23113254431257 is a deficient number, since it is larger than the sum of its proper divisors (1).

23113254431257 is an equidigital number, since it uses as much as digits as its factorization.

23113254431257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 604800, while the sum is 43.

Adding to 23113254431257 its reverse (75213445231132), we get a palindrome (98326699662389).

The spelling of 23113254431257 in words is "twenty-three trillion, one hundred thirteen billion, two hundred fifty-four million, four hundred thirty-one thousand, two hundred fifty-seven".