Base | Representation |
---|---|
bin | 1010100000101011111100… |
… | …00100000110100000111111 |
3 | 10000211121112222200201221202 |
4 | 11100111332010012200333 |
5 | 11012142102002234010 |
6 | 121054041415050115 |
7 | 4603611651420536 |
oct | 520257604064077 |
9 | 100747488621852 |
10 | 23113334024255 |
11 | 7401345547672 |
12 | 271362897093b |
13 | cb8768c76747 |
14 | 59c99704d31d |
15 | 2a136e2466a5 |
hex | 15057e10683f |
23113334024255 has 16 divisors (see below), whose sum is σ = 28052718932160. Its totient is φ = 18279597042432.
The previous prime is 23113334024219. The next prime is 23113334024273. The reversal of 23113334024255 is 55242043331132.
It is a cyclic number.
It is not a de Polignac number, because 23113334024255 - 224 = 23113317247039 is a prime.
It is a super-4 number, since 4×231133340242554 (a number of 55 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2239244 + ... + 7158273.
It is an arithmetic number, because the mean of its divisors is an integer number (1753294933260).
Almost surely, 223113334024255 is an apocalyptic number.
23113334024255 is a deficient number, since it is larger than the sum of its proper divisors (4939384907905).
23113334024255 is an equidigital number, since it uses as much as digits as its factorization.
23113334024255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9403138.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 23113334024255 its reverse (55242043331132), we get a palindrome (78355377355387).
The spelling of 23113334024255 in words is "twenty-three trillion, one hundred thirteen billion, three hundred thirty-four million, twenty-four thousand, two hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •