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231141034156033 is a prime number
BaseRepresentation
bin110100100011100010110111…
…001110111110000000000001
31010022101212102002101200200001
4310203202313032332000001
5220244003314220443113
62135332420350400001
766454250205221401
oct6443426716760001
91108355362350601
10231141034156033
11677153a8a46141
1221b10820800001
139bc86768946a1
144111400124801
151bac796ecc7dd
hexd238b73be001

231141034156033 has 2 divisors, whose sum is σ = 231141034156034. Its totient is φ = 231141034156032.

The previous prime is 231141034156013. The next prime is 231141034156037. The reversal of 231141034156033 is 330651430141132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 229819748277249 + 1321285878784 = 15159807^2 + 1149472^2 .

It is a cyclic number.

It is not a de Polignac number, because 231141034156033 - 25 = 231141034156001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231141034155983 and 231141034156001.

It is not a weakly prime, because it can be changed into another prime (231141034156037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115570517078016 + 115570517078017.

It is an arithmetic number, because the mean of its divisors is an integer number (115570517078017).

Almost surely, 2231141034156033 is an apocalyptic number.

It is an amenable number.

231141034156033 is a deficient number, since it is larger than the sum of its proper divisors (1).

231141034156033 is an equidigital number, since it uses as much as digits as its factorization.

231141034156033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 37.

Adding to 231141034156033 its reverse (330651430141132), we get a palindrome (561792464297165).

The spelling of 231141034156033 in words is "two hundred thirty-one trillion, one hundred forty-one billion, thirty-four million, one hundred fifty-six thousand, thirty-three".