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23114255354257 is a prime number
BaseRepresentation
bin1010100000101101101001…
…11110101100100110010001
310000211200221012100011010011
411100112310332230212101
511012200443332314012
6121054313050234521
74603643536535044
oct520266476544621
9100750835304104
1023114255354257
117401778618521
122713845425a41
13cb8884acaa22
1459ca4355cc5b
152a13c50881a7
hex1505b4fac991

23114255354257 has 2 divisors, whose sum is σ = 23114255354258. Its totient is φ = 23114255354256.

The previous prime is 23114255354191. The next prime is 23114255354341. The reversal of 23114255354257 is 75245355241132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12202173771921 + 10912081582336 = 3493161^2 + 3303344^2 .

It is a cyclic number.

It is not a de Polignac number, because 23114255354257 - 215 = 23114255321489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23114255354257.

It is not a weakly prime, because it can be changed into another prime (23114255352257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557127677128 + 11557127677129.

It is an arithmetic number, because the mean of its divisors is an integer number (11557127677129).

Almost surely, 223114255354257 is an apocalyptic number.

It is an amenable number.

23114255354257 is a deficient number, since it is larger than the sum of its proper divisors (1).

23114255354257 is an equidigital number, since it uses as much as digits as its factorization.

23114255354257 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5040000, while the sum is 49.

The spelling of 23114255354257 in words is "twenty-three trillion, one hundred fourteen billion, two hundred fifty-five million, three hundred fifty-four thousand, two hundred fifty-seven".