Base | Representation |
---|---|
bin | 110100100011101111010000… |
… | …010110010001111100111111 |
3 | 1010022110010202102110011210220 |
4 | 310203233100112101330333 |
5 | 220244213042120430210 |
6 | 2135342501001432423 |
7 | 66455231020403334 |
oct | 6443572026217477 |
9 | 1108403672404726 |
10 | 231154340405055 |
11 | 67720006a82a61 |
12 | 21b13314a9b713 |
13 | 9bc99b7541612 |
14 | 4111d0340c98b |
15 | 1baccc5274c70 |
hex | d23bd0591f3f |
231154340405055 has 32 divisors (see below), whose sum is σ = 378875151730944. Its totient is φ = 120307305693696.
The previous prime is 231154340405047. The next prime is 231154340405081. The reversal of 231154340405055 is 550504043451132.
It is not a de Polignac number, because 231154340405055 - 23 = 231154340405047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 231154340404998 and 231154340405016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1074679002 + ... + 1074894071.
It is an arithmetic number, because the mean of its divisors is an integer number (11839848491592).
Almost surely, 2231154340405055 is an apocalyptic number.
231154340405055 is a deficient number, since it is larger than the sum of its proper divisors (147720811325889).
231154340405055 is a wasteful number, since it uses less digits than its factorization.
231154340405055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2149573255.
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 231154340405055 its reverse (550504043451132), we get a palindrome (781658383856187).
The spelling of 231154340405055 in words is "two hundred thirty-one trillion, one hundred fifty-four billion, three hundred forty million, four hundred five thousand, fifty-five".
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