Base | Representation |
---|---|
bin | 1010100000111010010010… |
… | …11011111000101001011001 |
3 | 10000212100110002201201120201 |
4 | 11100131021123320221121 |
5 | 11012303342444013144 |
6 | 121101354250222201 |
7 | 4604303643556615 |
oct | 520351133705131 |
9 | 100770402651521 |
10 | 23121041001049 |
11 | 740463a976382 |
12 | 2715019a24961 |
13 | cb93c6892544 |
14 | 59d0c883c345 |
15 | 2a1670b601d4 |
hex | 1507496f8a59 |
23121041001049 has 2 divisors, whose sum is σ = 23121041001050. Its totient is φ = 23121041001048.
The previous prime is 23121041001011. The next prime is 23121041001139. The reversal of 23121041001049 is 94010014012132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16223720625424 + 6897320375625 = 4027868^2 + 2626275^2 .
It is a cyclic number.
It is not a de Polignac number, because 23121041001049 - 233 = 23112451066457 is a prime.
It is not a weakly prime, because it can be changed into another prime (23121041001449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11560520500524 + 11560520500525.
It is an arithmetic number, because the mean of its divisors is an integer number (11560520500525).
Almost surely, 223121041001049 is an apocalyptic number.
It is an amenable number.
23121041001049 is a deficient number, since it is larger than the sum of its proper divisors (1).
23121041001049 is an equidigital number, since it uses as much as digits as its factorization.
23121041001049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
The spelling of 23121041001049 in words is "twenty-three trillion, one hundred twenty-one billion, forty-one million, one thousand, forty-nine".
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