Base | Representation |
---|---|
bin | 100001101001010100101… |
… | …011100100010001000101 |
3 | 22012000222010201201201220 |
4 | 201221110223210101011 |
5 | 300340201424042013 |
6 | 4530100424110553 |
7 | 326021214120216 |
oct | 41512453442105 |
9 | 8160863651656 |
10 | 2312113112133 |
11 | 81161a636560 |
12 | 31412a005459 |
13 | 13a053aac546 |
14 | 7dc9a65540d |
15 | 40223d01b23 |
hex | 21a54ae4445 |
2312113112133 has 16 divisors (see below), whose sum is σ = 3363158323200. Its totient is φ = 1401245380080.
The previous prime is 2312113112129. The next prime is 2312113112149. The reversal of 2312113112133 is 3312113112132.
It is not a de Polignac number, because 2312113112133 - 22 = 2312113112129 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2312113122133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479058 + ... + 2203116.
It is an arithmetic number, because the mean of its divisors is an integer number (210197395200).
Almost surely, 22312113112133 is an apocalyptic number.
It is an amenable number.
2312113112133 is a deficient number, since it is larger than the sum of its proper divisors (1051045211067).
2312113112133 is a wasteful number, since it uses less digits than its factorization.
2312113112133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1764712.
The product of its digits is 648, while the sum is 24.
Adding to 2312113112133 its reverse (3312113112132), we get a palindrome (5624226224265).
Subtracting 2312113112133 from its reverse (3312113112132), we obtain a palindrome (999999999999).
The spelling of 2312113112133 in words is "two trillion, three hundred twelve billion, one hundred thirteen million, one hundred twelve thousand, one hundred thirty-three".
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