2312121211133 has 4 divisors (see below), whose sum is σ = 2312526070848. Its totient is φ = 2311716351420.

The previous prime is 2312121211091. The next prime is 2312121211187. The reversal of 2312121211133 is 3311121212132.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2312121211133 - 2¹⁸ = 2312120948989 is a prime.

It is a super-2 number, since 2×2312121211133² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2312121211099 and 2312121211108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2312121211633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202421291 + ... + 202432712.

It is an arithmetic number, because the mean of its divisors is an integer number (578131517712).

Almost surely, 2^{2312121211133} is an apocalyptic number.

It is an amenable number.

2312121211133 is a deficient number, since it is larger than the sum of its proper divisors (404859715).

2312121211133 is an equidigital number, since it uses as much as digits as its factorization.

2312121211133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404859714.

The product of its digits is 432, while the sum is 23.

Adding to 2312121211133 its reverse (3311121212132), we get a palindrome (5623242423265).

Subtracting 2312121211133 from its reverse (3311121212132), we obtain a palindrome (999000000999).

The spelling of 2312121211133 in words is "two trillion, three hundred twelve billion, one hundred twenty-one million, two hundred eleven thousand, one hundred thirty-three".