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2312134677401 is a prime number
BaseRepresentation
bin100001101001010101111…
…101110101001110011001
322012001000122022100201112
4201221111331311032121
5300340222434134101
64530102514230105
7326021565325553
oct41512575651631
98161018270645
102312134677401
1181163082589a
12314135285335
1313a0583c0263
147dc9d46a4d3
1540225b616bb
hex21a55f75399

2312134677401 has 2 divisors, whose sum is σ = 2312134677402. Its totient is φ = 2312134677400.

The previous prime is 2312134677299. The next prime is 2312134677427. The reversal of 2312134677401 is 1047764312132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1285457088400 + 1026677589001 = 1133780^2 + 1013251^2 .

It is a cyclic number.

It is not a de Polignac number, because 2312134677401 - 214 = 2312134661017 is a prime.

It is a super-2 number, since 2×23121346774012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2312134677491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156067338700 + 1156067338701.

It is an arithmetic number, because the mean of its divisors is an integer number (1156067338701).

Almost surely, 22312134677401 is an apocalyptic number.

It is an amenable number.

2312134677401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2312134677401 is an equidigital number, since it uses as much as digits as its factorization.

2312134677401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 169344, while the sum is 41.

Adding to 2312134677401 its reverse (1047764312132), we get a palindrome (3359898989533).

The spelling of 2312134677401 in words is "two trillion, three hundred twelve billion, one hundred thirty-four million, six hundred seventy-seven thousand, four hundred one".