Base | Representation |
---|---|
bin | 1010100000111110100011… |
… | …11100010100011101101011 |
3 | 10000212120100201011010202012 |
4 | 11100133101330110131223 |
5 | 11012323040242024341 |
6 | 121102413421230135 |
7 | 4604414463151154 |
oct | 520372174243553 |
9 | 100776321133665 |
10 | 23123331204971 |
11 | 7405605706498 |
12 | 2715558a0234b |
13 | cb96a01b78aa |
14 | 59d264a7a92b |
15 | 2a1756c490eb |
hex | 1507d1f1476b |
23123331204971 has 2 divisors, whose sum is σ = 23123331204972. Its totient is φ = 23123331204970.
The previous prime is 23123331204931. The next prime is 23123331204997. The reversal of 23123331204971 is 17940213332132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23123331204971 is a prime.
It is a super-2 number, since 2×231233312049712 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (23123331204931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11561665602485 + 11561665602486.
It is an arithmetic number, because the mean of its divisors is an integer number (11561665602486).
Almost surely, 223123331204971 is an apocalyptic number.
23123331204971 is a deficient number, since it is larger than the sum of its proper divisors (1).
23123331204971 is an equidigital number, since it uses as much as digits as its factorization.
23123331204971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296, while the sum is 41.
The spelling of 23123331204971 in words is "twenty-three trillion, one hundred twenty-three billion, three hundred thirty-one million, two hundred four thousand, nine hundred seventy-one".
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