231240141042133 has 4 divisors (see below), whose sum is σ = 231245649031168. Its totient is φ = 231234633053100.

The previous prime is 231240141042077. The next prime is 231240141042143. The reversal of 231240141042133 is 331240141042132.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 231240141042133 - 2⁴⁵ = 196055768953301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231240141042095 and 231240141042104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231240141042143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2753931543 + ... + 2754015508.

It is an arithmetic number, because the mean of its divisors is an integer number (57811412257792).

Almost surely, 2^{231240141042133} is an apocalyptic number.

It is an amenable number.

231240141042133 is a deficient number, since it is larger than the sum of its proper divisors (5507989035).

231240141042133 is an equidigital number, since it uses as much as digits as its factorization.

231240141042133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5507989034.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 231240141042133 its reverse (331240141042132), we get a palindrome (562480282084265).

Subtracting 231240141042133 from its reverse (331240141042132), we obtain a palindrome (99999999999999).

The spelling of 231240141042133 in words is "two hundred thirty-one trillion, two hundred forty billion, one hundred forty-one million, forty-two thousand, one hundred thirty-three".