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231241134103 = 733034447729
BaseRepresentation
bin1101011101011100001…
…0111011000000010111
3211002212120222201210021
43113113002323000113
512242040212242403
6254121500010011
722464241131430
oct3272702730027
9732776881707
10231241134103
118a0836566a1
1238996230907
1318a6287b545
14b2992c6487
1560360118bd
hex35d70bb017

231241134103 has 4 divisors (see below), whose sum is σ = 264275581840. Its totient is φ = 198206686368.

The previous prime is 231241134071. The next prime is 231241134167. The reversal of 231241134103 is 301431142132.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 231241134103 - 25 = 231241134071 is a prime.

It is a super-2 number, since 2×2312411341032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231241132103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16517223858 + ... + 16517223871.

It is an arithmetic number, because the mean of its divisors is an integer number (66068895460).

Almost surely, 2231241134103 is an apocalyptic number.

231241134103 is a deficient number, since it is larger than the sum of its proper divisors (33034447737).

231241134103 is an equidigital number, since it uses as much as digits as its factorization.

231241134103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33034447736.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 231241134103 its reverse (301431142132), we get a palindrome (532672276235).

The spelling of 231241134103 in words is "two hundred thirty-one billion, two hundred forty-one million, one hundred thirty-four thousand, one hundred three".

Divisors: 1 7 33034447729 231241134103