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2312601401045 = 513318912895427
BaseRepresentation
bin100001101001110001110…
…010001111011011010101
322012002020011112101012102
4201221301302033123111
5300342201424313140
64530221105531445
7326036263400105
oct41516162173325
98162204471172
102312601401045
11811850224211
12314245643b85
1313a100cc3cb0
147dd0543d205
1540251b04e15
hex21a71c8f6d5

2312601401045 has 32 divisors (see below), whose sum is σ = 3119661941760. Its totient is φ = 1634108382720.

The previous prime is 2312601400999. The next prime is 2312601401051. The reversal of 2312601401045 is 5401041062132.

It is not a de Polignac number, because 2312601401045 - 226 = 2312534292181 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2312601400999 and 2312601401017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6268379 + ... + 6627048.

It is an arithmetic number, because the mean of its divisors is an integer number (97489435680).

Almost surely, 22312601401045 is an apocalyptic number.

It is an amenable number.

2312601401045 is a deficient number, since it is larger than the sum of its proper divisors (807060540715).

2312601401045 is a wasteful number, since it uses less digits than its factorization.

2312601401045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12895565.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 2312601401045 its reverse (5401041062132), we get a palindrome (7713642463177).

The spelling of 2312601401045 in words is "two trillion, three hundred twelve billion, six hundred one million, four hundred one thousand, forty-five".

Divisors: 1 5 13 31 65 89 155 403 445 1157 2015 2759 5785 13795 35867 179335 12895427 64477135 167640551 399758237 838202755 1147693003 1998791185 5196857081 5738465015 14920009039 25984285405 35578483093 74600045195 177892415465 462520280209 2312601401045