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23126621342017 is a prime number
BaseRepresentation
bin1010100001000100101100…
…00011001100100101000001
310000212212212000010102021211
411100202112003030211001
511012401310030421032
6121104120112250121
74604562143644354
oct520422603144501
9100785760112254
1023126621342017
117406a43924116
122716116840941
13cb9aa5a2584b
1459d497a0a29b
152a189a9ee747
hex1508960cc941

23126621342017 has 2 divisors, whose sum is σ = 23126621342018. Its totient is φ = 23126621342016.

The previous prime is 23126621341979. The next prime is 23126621342039. The reversal of 23126621342017 is 71024312662132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23081865400881 + 44755941136 = 4804359^2 + 211556^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23126621342017 is a prime.

It is a super-2 number, since 2×231266213420172 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23126621342317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11563310671008 + 11563310671009.

It is an arithmetic number, because the mean of its divisors is an integer number (11563310671009).

Almost surely, 223126621342017 is an apocalyptic number.

It is an amenable number.

23126621342017 is a deficient number, since it is larger than the sum of its proper divisors (1).

23126621342017 is an equidigital number, since it uses as much as digits as its factorization.

23126621342017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 40.

The spelling of 23126621342017 in words is "twenty-three trillion, one hundred twenty-six billion, six hundred twenty-one million, three hundred forty-two thousand, seventeen".