Base | Representation |
---|---|
bin | 100001101010010000000… |
… | …110011001100110110101 |
3 | 22012010112121112222200120 |
4 | 201222100012121212311 |
5 | 300344222130031401 |
6 | 4530343355002153 |
7 | 326055010416033 |
oct | 41522006314665 |
9 | 8163477488616 |
10 | 2313110002101 |
11 | 811a91325768 |
12 | 314367a39359 |
13 | 13a18249ac72 |
14 | 7dd52bd3553 |
15 | 402815bb836 |
hex | 21a901999b5 |
2313110002101 has 4 divisors (see below), whose sum is σ = 3084146669472. Its totient is φ = 1542073334732.
The previous prime is 2313110002081. The next prime is 2313110002141. The reversal of 2313110002101 is 1012000113132.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2313110002101 - 26 = 2313110002037 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2313110002141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385518333681 + ... + 385518333686.
It is an arithmetic number, because the mean of its divisors is an integer number (771036667368).
Almost surely, 22313110002101 is an apocalyptic number.
It is an amenable number.
2313110002101 is a deficient number, since it is larger than the sum of its proper divisors (771036667371).
2313110002101 is an equidigital number, since it uses as much as digits as its factorization.
2313110002101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 771036667370.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 2313110002101 its reverse (1012000113132), we get a palindrome (3325110115233).
The spelling of 2313110002101 in words is "two trillion, three hundred thirteen billion, one hundred ten million, two thousand, one hundred one".
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