Base | Representation |
---|---|
bin | 110100100110000001010000… |
… | …100111110100111010110111 |
3 | 1010100000010102001120100112212 |
4 | 310212001100213310322313 |
5 | 220304300123443423111 |
6 | 2135542505122204035 |
7 | 66502450654203263 |
oct | 6446012047647267 |
9 | 1110003361510485 |
10 | 231311111311031 |
11 | 67780545080a74 |
12 | 21b397871b361b |
13 | 9c0b70c7c3bcb |
14 | 41197361230a3 |
15 | 1bb1ded4b898b |
hex | d260509f4eb7 |
231311111311031 has 4 divisors (see below), whose sum is σ = 232009936421064. Its totient is φ = 230612286201000.
The previous prime is 231311111310997. The next prime is 231311111311073. The reversal of 231311111311031 is 130113111113132.
It is a happy number.
231311111311031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 231311111311031 - 210 = 231311111310007 is a prime.
It is a super-2 number, since 2×2313111113110312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 231311111310988 and 231311111311006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (231311111311831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349412554520 + ... + 349412555181.
It is an arithmetic number, because the mean of its divisors is an integer number (58002484105266).
Almost surely, 2231311111311031 is an apocalyptic number.
231311111311031 is a deficient number, since it is larger than the sum of its proper divisors (698825110033).
231311111311031 is an equidigital number, since it uses as much as digits as its factorization.
231311111311031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 698825110032.
The product of its (nonzero) digits is 162, while the sum is 23.
Adding to 231311111311031 its reverse (130113111113132), we get a palindrome (361424222424163).
The spelling of 231311111311031 in words is "two hundred thirty-one trillion, three hundred eleven billion, one hundred eleven million, three hundred eleven thousand, thirty-one".
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