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2313140432101 = 4493514832057
BaseRepresentation
bin100001101010010001111…
…010011110110011100101
322012010121201210222210121
4201222101322132303211
5300344302422311401
64530350403121541
7326055530155162
oct41522172366345
98163551728717
102313140432101
11811aa751a224
123143760732b1
1313a188893895
147dd56c75069
15402840ccca1
hex21a91e9ece5

2313140432101 has 4 divisors (see below), whose sum is σ = 2313655268652. Its totient is φ = 2312625595552.

The previous prime is 2313140432089. The next prime is 2313140432117. The reversal of 2313140432101 is 1012340413132.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2242952527201 + 70187904900 = 1497649^2 + 264930^2 .

It is a cyclic number.

It is not a de Polignac number, because 2313140432101 - 211 = 2313140430053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2313140433101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257411536 + ... + 257420521.

It is an arithmetic number, because the mean of its divisors is an integer number (578413817163).

Almost surely, 22313140432101 is an apocalyptic number.

It is an amenable number.

2313140432101 is a deficient number, since it is larger than the sum of its proper divisors (514836551).

2313140432101 is an equidigital number, since it uses as much as digits as its factorization.

2313140432101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 514836550.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2313140432101 its reverse (1012340413132), we get a palindrome (3325480845233).

The spelling of 2313140432101 in words is "two trillion, three hundred thirteen billion, one hundred forty million, four hundred thirty-two thousand, one hundred one".

Divisors: 1 4493 514832057 2313140432101