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231411314412073 is a prime number
BaseRepresentation
bin110100100111011110100101…
…001100010100101000101001
31010100100201001101101022001101
4310213132211030110220221
5220312420332442141243
62140100520142321401
766512626045413145
oct6447364514245051
91110321041338041
10231411314412073
1167809a95117974
1221b55090b89261
139c17cbb405283
144120520132225
151bb481547154d
hexd277a5314a29

231411314412073 has 2 divisors, whose sum is σ = 231411314412074. Its totient is φ = 231411314412072.

The previous prime is 231411314412049. The next prime is 231411314412079. The reversal of 231411314412073 is 370214413114132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124846923474064 + 106564390938009 = 11173492^2 + 10323003^2 .

It is a cyclic number.

It is not a de Polignac number, because 231411314412073 - 225 = 231411280857641 is a prime.

It is a super-3 number, since 3×2314113144120733 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (231411314412079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115705657206036 + 115705657206037.

It is an arithmetic number, because the mean of its divisors is an integer number (115705657206037).

Almost surely, 2231411314412073 is an apocalyptic number.

It is an amenable number.

231411314412073 is a deficient number, since it is larger than the sum of its proper divisors (1).

231411314412073 is an equidigital number, since it uses as much as digits as its factorization.

231411314412073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

The spelling of 231411314412073 in words is "two hundred thirty-one trillion, four hundred eleven billion, three hundred fourteen million, four hundred twelve thousand, seventy-three".