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231421433 is a prime number
BaseRepresentation
bin11011100101100…
…11010111111001
3121010110102112012
431302303113321
5433220441213
634544055305
75510023025
oct1562632771
9533412465
10231421433
111096a4391
1265604535
1338c39279
1422a41385
15154b44a8
hexdcb35f9

231421433 has 2 divisors, whose sum is σ = 231421434. Its totient is φ = 231421432.

The previous prime is 231421409. The next prime is 231421439. The reversal of 231421433 is 334124132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 192321424 + 39100009 = 13868^2 + 6253^2 .

It is a cyclic number.

It is not a de Polignac number, because 231421433 - 216 = 231355897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231421399 and 231421408.

It is not a weakly prime, because it can be changed into another prime (231421439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115710716 + 115710717.

It is an arithmetic number, because the mean of its divisors is an integer number (115710717).

Almost surely, 2231421433 is an apocalyptic number.

It is an amenable number.

231421433 is a deficient number, since it is larger than the sum of its proper divisors (1).

231421433 is an equidigital number, since it uses as much as digits as its factorization.

231421433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 23.

The square root of 231421433 is about 15212.5419637876. The cubic root of 231421433 is about 613.9521522625.

Adding to 231421433 its reverse (334124132), we get a palindrome (565545565).

The spelling of 231421433 in words is "two hundred thirty-one million, four hundred twenty-one thousand, four hundred thirty-three".