Base | Representation |
---|---|
bin | 100001101011011110010… |
… | …100000111101001100011 |
3 | 22012020221001201122011202 |
4 | 201223132110013221203 |
5 | 300404414042041121 |
6 | 4531121512231415 |
7 | 326132353201226 |
oct | 41533624075143 |
9 | 8166831648152 |
10 | 2314422221411 |
11 | 8125a5009533 |
12 | 31467339b56b |
13 | 13a3312c39b1 |
14 | 800391b55bd |
15 | 4030b8c240b |
hex | 21ade507a63 |
2314422221411 has 2 divisors, whose sum is σ = 2314422221412. Its totient is φ = 2314422221410.
The previous prime is 2314422221213. The next prime is 2314422221417. The reversal of 2314422221411 is 1141222244132.
2314422221411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2314422221411 - 210 = 2314422220387 is a prime.
It is a super-2 number, since 2×23144222214112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2314422221417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157211110705 + 1157211110706.
It is an arithmetic number, because the mean of its divisors is an integer number (1157211110706).
Almost surely, 22314422221411 is an apocalyptic number.
2314422221411 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314422221411 is an equidigital number, since it uses as much as digits as its factorization.
2314422221411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6144, while the sum is 29.
Adding to 2314422221411 its reverse (1141222244132), we get a palindrome (3455644465543).
The spelling of 2314422221411 in words is "two trillion, three hundred fourteen billion, four hundred twenty-two million, two hundred twenty-one thousand, four hundred eleven".
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