Base | Representation |
---|---|
bin | 1010100001100101011111… |
… | …10111110110001010001011 |
3 | 10000221120022111021200012012 |
4 | 11100302233313312022023 |
5 | 11013143343004142103 |
6 | 121120151534210135 |
7 | 4606054463562233 |
oct | 520625767661213 |
9 | 100846274250165 |
10 | 23144234443403 |
11 | 7413461a79957 |
12 | 271961135394b |
13 | cbb651a50c28 |
14 | 5a0288cc2cc3 |
15 | 2a207be312d8 |
hex | 150cafdf628b |
23144234443403 has 2 divisors, whose sum is σ = 23144234443404. Its totient is φ = 23144234443402.
The previous prime is 23144234443399. The next prime is 23144234443423. The reversal of 23144234443403 is 30434443244132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23144234443403 - 22 = 23144234443399 is a prime.
It is not a weakly prime, because it can be changed into another prime (23144234443423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11572117221701 + 11572117221702.
It is an arithmetic number, because the mean of its divisors is an integer number (11572117221702).
Almost surely, 223144234443403 is an apocalyptic number.
23144234443403 is a deficient number, since it is larger than the sum of its proper divisors (1).
23144234443403 is an equidigital number, since it uses as much as digits as its factorization.
23144234443403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1327104, while the sum is 41.
Adding to 23144234443403 its reverse (30434443244132), we get a palindrome (53578677687535).
The spelling of 23144234443403 in words is "twenty-three trillion, one hundred forty-four billion, two hundred thirty-four million, four hundred forty-three thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •