Base | Representation |
---|---|
bin | 1101011110010111111… |
… | …1111100001101111001 |
3 | 211010112002001121000111 |
4 | 3113211333330031321 |
5 | 12243043423321443 |
6 | 254202421104321 |
7 | 22503405424534 |
oct | 3274577741571 |
9 | 733462047014 |
10 | 231492010873 |
11 | 8a1a2229072 |
12 | 38a462580a1 |
13 | 18aa283a036 |
14 | b2c074da1b |
15 | 604d06a69d |
hex | 35e5ffc379 |
231492010873 has 2 divisors, whose sum is σ = 231492010874. Its totient is φ = 231492010872.
The previous prime is 231492010837. The next prime is 231492010879. The reversal of 231492010873 is 378010294132.
Together with previous prime (231492010837) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 231402367849 + 89643024 = 481043^2 + 9468^2 .
It is a cyclic number.
It is not a de Polignac number, because 231492010873 - 233 = 222902076281 is a prime.
It is not a weakly prime, because it can be changed into another prime (231492010879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115746005436 + 115746005437.
It is an arithmetic number, because the mean of its divisors is an integer number (115746005437).
Almost surely, 2231492010873 is an apocalyptic number.
It is an amenable number.
231492010873 is a deficient number, since it is larger than the sum of its proper divisors (1).
231492010873 is an equidigital number, since it uses as much as digits as its factorization.
231492010873 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 231492010873 in words is "two hundred thirty-one billion, four hundred ninety-two million, ten thousand, eight hundred seventy-three".
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