Base | Representation |
---|---|
bin | 1010100001110010100010… |
… | …00010000010101010101011 |
3 | 10000222020101020201010010111 |
4 | 11100321101002002222223 |
5 | 11013302211200341042 |
6 | 121123310230155151 |
7 | 4606423066264462 |
oct | 520712102025253 |
9 | 100866336633114 |
10 | 23151233215147 |
11 | 7416423664734 |
12 | 271aa451b2ab7 |
13 | cbc1c8a16a9b |
14 | 5a07505dd9d9 |
15 | 2a233b5a6517 |
hex | 150e51082aab |
23151233215147 has 2 divisors, whose sum is σ = 23151233215148. Its totient is φ = 23151233215146.
The previous prime is 23151233215073. The next prime is 23151233215169. The reversal of 23151233215147 is 74151233215132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23151233215147 - 211 = 23151233213099 is a prime.
It is not a weakly prime, because it can be changed into another prime (23151233255147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11575616607573 + 11575616607574.
It is an arithmetic number, because the mean of its divisors is an integer number (11575616607574).
Almost surely, 223151233215147 is an apocalyptic number.
23151233215147 is a deficient number, since it is larger than the sum of its proper divisors (1).
23151233215147 is an equidigital number, since it uses as much as digits as its factorization.
23151233215147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 151200, while the sum is 40.
The spelling of 23151233215147 in words is "twenty-three trillion, one hundred fifty-one billion, two hundred thirty-three million, two hundred fifteen thousand, one hundred forty-seven".
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