Base | Representation |
---|---|
bin | 10101100011111101… |
… | …111111101010110001 |
3 | 2012202111122002212201 |
4 | 111203331333222301 |
5 | 334403410014213 |
6 | 14345204223201 |
7 | 1446505012555 |
oct | 254375775261 |
9 | 65674562781 |
10 | 23152032433 |
11 | 990079a702 |
12 | 45a169ab01 |
13 | 224c72019a |
14 | 1198b85865 |
15 | 9078416dd |
hex | 563f7fab1 |
23152032433 has 2 divisors, whose sum is σ = 23152032434. Its totient is φ = 23152032432.
The previous prime is 23152032413. The next prime is 23152032443. The reversal of 23152032433 is 33423025132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18842503824 + 4309528609 = 137268^2 + 65647^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23152032433 is a prime.
It is not a weakly prime, because it can be changed into another prime (23152032413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11576016216 + 11576016217.
It is an arithmetic number, because the mean of its divisors is an integer number (11576016217).
Almost surely, 223152032433 is an apocalyptic number.
It is an amenable number.
23152032433 is a deficient number, since it is larger than the sum of its proper divisors (1).
23152032433 is an equidigital number, since it uses as much as digits as its factorization.
23152032433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 23152032433 its reverse (33423025132), we get a palindrome (56575057565).
The spelling of 23152032433 in words is "twenty-three billion, one hundred fifty-two million, thirty-two thousand, four hundred thirty-three".
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