Base | Representation |
---|---|
bin | 101100001010… |
… | …0110101011101 |
3 | 1121120100100001 |
4 | 1120110311131 |
5 | 21411412023 |
6 | 2144134301 |
7 | 400543261 |
oct | 130246535 |
9 | 47510301 |
10 | 23154013 |
11 | 12084a53 |
12 | 7907391 |
13 | 4a48bcc |
14 | 310a0a1 |
15 | 20756ad |
hex | 1614d5d |
23154013 has 4 divisors (see below), whose sum is σ = 23164380. Its totient is φ = 23143648.
The previous prime is 23154011. The next prime is 23154029. The reversal of 23154013 is 31045132.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 11580409 + 11573604 = 3403^2 + 3402^2 .
It is a cyclic number.
It is not a de Polignac number, because 23154013 - 21 = 23154011 is a prime.
It is a super-2 number, since 2×231540132 = 1072216636008338, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23154011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298 + ... + 6811.
It is an arithmetic number, because the mean of its divisors is an integer number (5791095).
Almost surely, 223154013 is an apocalyptic number.
23154013 is the 3403-rd centered square number.
It is an amenable number.
23154013 is a deficient number, since it is larger than the sum of its proper divisors (10367).
23154013 is an equidigital number, since it uses as much as digits as its factorization.
23154013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10366.
The product of its (nonzero) digits is 360, while the sum is 19.
The square root of 23154013 is about 4811.8616979294. The cubic root of 23154013 is about 285.0200580938.
Adding to 23154013 its reverse (31045132), we get a palindrome (54199145).
It can be divided in two parts, 2315 and 4013, that added together give a triangular number (6328 = T112).
The spelling of 23154013 in words is "twenty-three million, one hundred fifty-four thousand, thirteen".
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