Base | Representation |
---|---|
bin | 100001101100011010111… |
… | …111000011101011111011 |
3 | 22012100120000001202021101 |
4 | 201230122333003223323 |
5 | 300414010132012311 |
6 | 4531410513152231 |
7 | 326166523126345 |
oct | 41543277035373 |
9 | 8170500052241 |
10 | 2315440110331 |
11 | 812a77640547 |
12 | 3148b825b677 |
13 | 13a46415542a |
14 | 800d445c295 |
15 | 4036ae38ec1 |
hex | 21b1afc3afb |
2315440110331 has 2 divisors, whose sum is σ = 2315440110332. Its totient is φ = 2315440110330.
The previous prime is 2315440110323. The next prime is 2315440110337. The reversal of 2315440110331 is 1330110445132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2315440110331 - 23 = 2315440110323 is a prime.
It is a super-2 number, since 2×23154401103312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2315440110331.
It is not a weakly prime, because it can be changed into another prime (2315440110337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157720055165 + 1157720055166.
It is an arithmetic number, because the mean of its divisors is an integer number (1157720055166).
Almost surely, 22315440110331 is an apocalyptic number.
2315440110331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2315440110331 is an equidigital number, since it uses as much as digits as its factorization.
2315440110331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 2315440110331 its reverse (1330110445132), we get a palindrome (3645550555463).
The spelling of 2315440110331 in words is "two trillion, three hundred fifteen billion, four hundred forty million, one hundred ten thousand, three hundred thirty-one".
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