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231545551543331 is a prime number
BaseRepresentation
bin110100101001011011100110…
…010110010101110000100011
31010100211112112121020010001112
4310221123212112111300203
5220322120242143341311
62140242320302053535
766525420422250644
oct6451334626256043
91110745477203045
10231545551543331
1167860a0a514473
1221b770b487a2ab
139c2786208665c
144126c1623b6cb
151bb807029b28b
hexd296e6595c23

231545551543331 has 2 divisors, whose sum is σ = 231545551543332. Its totient is φ = 231545551543330.

The previous prime is 231545551543309. The next prime is 231545551543343. The reversal of 231545551543331 is 133345155545132.

231545551543331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 231545551543331 - 210 = 231545551542307 is a prime.

It is a super-2 number, since 2×2315455515433312 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 231545551543331.

It is not a weakly prime, because it can be changed into another prime (231545551573331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115772775771665 + 115772775771666.

It is an arithmetic number, because the mean of its divisors is an integer number (115772775771666).

Almost surely, 2231545551543331 is an apocalyptic number.

231545551543331 is a deficient number, since it is larger than the sum of its proper divisors (1).

231545551543331 is an equidigital number, since it uses as much as digits as its factorization.

231545551543331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8100000, while the sum is 50.

The spelling of 231545551543331 in words is "two hundred thirty-one trillion, five hundred forty-five billion, five hundred fifty-one million, five hundred forty-three thousand, three hundred thirty-one".