Base | Representation |
---|---|
bin | 110100101011101110111000… |
… | …000110111010001010010011 |
3 | 1010101101122201111202111101102 |
4 | 310223232320012322022103 |
5 | 220332213124010124042 |
6 | 2140443112220055015 |
7 | 66543016266102533 |
oct | 6453567006721223 |
9 | 1111348644674342 |
10 | 231703689536147 |
11 | 67911a8a271014 |
12 | 21ba188899446b |
13 | 9c3974463277a |
14 | 41307387374c3 |
15 | 1bbc228532b32 |
hex | d2bbb81ba293 |
231703689536147 has 2 divisors, whose sum is σ = 231703689536148. Its totient is φ = 231703689536146.
The previous prime is 231703689536129. The next prime is 231703689536153. The reversal of 231703689536147 is 741635986307132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231703689536147 - 26 = 231703689536083 is a prime.
It is not a weakly prime, because it can be changed into another prime (231703689536197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115851844768073 + 115851844768074.
It is an arithmetic number, because the mean of its divisors is an integer number (115851844768074).
It is a 1-persistent number, because it is pandigital, but 2⋅231703689536147 = 463407379072294 is not.
Almost surely, 2231703689536147 is an apocalyptic number.
231703689536147 is a deficient number, since it is larger than the sum of its proper divisors (1).
231703689536147 is an equidigital number, since it uses as much as digits as its factorization.
231703689536147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 137168640, while the sum is 65.
The spelling of 231703689536147 in words is "two hundred thirty-one trillion, seven hundred three billion, six hundred eighty-nine million, five hundred thirty-six thousand, one hundred forty-seven".
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