Base | Representation |
---|---|
bin | 1010100010011100111111… |
… | …11111001011011011010011 |
3 | 10001001102020011222000012121 |
4 | 11101032133333023123103 |
5 | 11014140404332414024 |
6 | 121142000442235111 |
7 | 4611161063566225 |
oct | 521163777133323 |
9 | 101042204860177 |
10 | 23174032701139 |
11 | 742506334aa41 |
12 | 27233487b5a97 |
13 | cc13c039b9b8 |
14 | 5a18b4614415 |
15 | 2a2c22ea98e4 |
hex | 15139ffcb6d3 |
23174032701139 has 2 divisors, whose sum is σ = 23174032701140. Its totient is φ = 23174032701138.
The previous prime is 23174032701121. The next prime is 23174032701151. The reversal of 23174032701139 is 93110723047132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23174032701139 - 241 = 20975009445587 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23174032701095 and 23174032701104.
It is not a weakly prime, because it can be changed into another prime (23174032701109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11587016350569 + 11587016350570.
It is an arithmetic number, because the mean of its divisors is an integer number (11587016350570).
Almost surely, 223174032701139 is an apocalyptic number.
23174032701139 is a deficient number, since it is larger than the sum of its proper divisors (1).
23174032701139 is an equidigital number, since it uses as much as digits as its factorization.
23174032701139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 190512, while the sum is 43.
The spelling of 23174032701139 in words is "twenty-three trillion, one hundred seventy-four billion, thirty-two million, seven hundred one thousand, one hundred thirty-nine".
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