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23184140113 is a prime number
BaseRepresentation
bin10101100101111000…
…011110011101010001
32012211202001100100001
4111211320132131101
5334440114440423
614352312330001
71450344640141
oct254570363521
965752040301
1023184140113
11991792a682
1245b03a3901
132256282604
14119d142921
1590a584cad
hex565e1e751

23184140113 has 2 divisors, whose sum is σ = 23184140114. Its totient is φ = 23184140112.

The previous prime is 23184140059. The next prime is 23184140129. The reversal of 23184140113 is 31104148132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20622970449 + 2561169664 = 143607^2 + 50608^2 .

It is a cyclic number.

It is not a de Polignac number, because 23184140113 - 213 = 23184131921 is a prime.

It is not a weakly prime, because it can be changed into another prime (23184140513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11592070056 + 11592070057.

It is an arithmetic number, because the mean of its divisors is an integer number (11592070057).

Almost surely, 223184140113 is an apocalyptic number.

It is an amenable number.

23184140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

23184140113 is an equidigital number, since it uses as much as digits as its factorization.

23184140113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 23184140113 its reverse (31104148132), we get a palindrome (54288288245).

The spelling of 23184140113 in words is "twenty-three billion, one hundred eighty-four million, one hundred forty thousand, one hundred thirteen".