Base | Representation |
---|---|
bin | 10101100101111000… |
… | …011110011101010001 |
3 | 2012211202001100100001 |
4 | 111211320132131101 |
5 | 334440114440423 |
6 | 14352312330001 |
7 | 1450344640141 |
oct | 254570363521 |
9 | 65752040301 |
10 | 23184140113 |
11 | 991792a682 |
12 | 45b03a3901 |
13 | 2256282604 |
14 | 119d142921 |
15 | 90a584cad |
hex | 565e1e751 |
23184140113 has 2 divisors, whose sum is σ = 23184140114. Its totient is φ = 23184140112.
The previous prime is 23184140059. The next prime is 23184140129. The reversal of 23184140113 is 31104148132.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20622970449 + 2561169664 = 143607^2 + 50608^2 .
It is a cyclic number.
It is not a de Polignac number, because 23184140113 - 213 = 23184131921 is a prime.
It is not a weakly prime, because it can be changed into another prime (23184140513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11592070056 + 11592070057.
It is an arithmetic number, because the mean of its divisors is an integer number (11592070057).
Almost surely, 223184140113 is an apocalyptic number.
It is an amenable number.
23184140113 is a deficient number, since it is larger than the sum of its proper divisors (1).
23184140113 is an equidigital number, since it uses as much as digits as its factorization.
23184140113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 23184140113 its reverse (31104148132), we get a palindrome (54288288245).
The spelling of 23184140113 in words is "twenty-three billion, one hundred eighty-four million, one hundred forty thousand, one hundred thirteen".
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