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2319944953 is a prime number
BaseRepresentation
bin1000101001000111…
…1000110011111001
312222200101102012011
42022101320303321
514222401214303
61022112245521
7111330130624
oct21221706371
95880342164
102319944953
11a90603a87
12548b408a1
132ac8394c1
14180180dbb
15d8a1116d
hex8a478cf9

2319944953 has 2 divisors, whose sum is σ = 2319944954. Its totient is φ = 2319944952.

The previous prime is 2319944927. The next prime is 2319944969. The reversal of 2319944953 is 3594499132.

2319944953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2236533264 + 83411689 = 47292^2 + 9133^2 .

It is a cyclic number.

It is not a de Polignac number, because 2319944953 - 213 = 2319936761 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2319944897 and 2319944906.

It is not a weakly prime, because it can be changed into another prime (2319944903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1159972476 + 1159972477.

It is an arithmetic number, because the mean of its divisors is an integer number (1159972477).

Almost surely, 22319944953 is an apocalyptic number.

It is an amenable number.

2319944953 is a deficient number, since it is larger than the sum of its proper divisors (1).

2319944953 is an equidigital number, since it uses as much as digits as its factorization.

2319944953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1049760, while the sum is 49.

The square root of 2319944953 is about 48165.8068862134. The cubic root of 2319944953 is about 1323.8107193522.

The spelling of 2319944953 in words is "two billion, three hundred nineteen million, nine hundred forty-four thousand, nine hundred fifty-three".