Base | Representation |
---|---|
bin | 110100110000100001110001… |
… | …001000110010111001100011 |
3 | 1010102120011021110011001012022 |
4 | 310300201301020302321203 |
5 | 220403113004100031042 |
6 | 2141254330303452055 |
7 | 66605563166120363 |
oct | 6460416110627143 |
9 | 1112504243131168 |
10 | 232033211330147 |
11 | 67a29806780077 |
12 | 22035710bb702b |
13 | 9c6183a732226 |
14 | 41426785a29a3 |
15 | 1bc5ab2859cd2 |
hex | d30871232e63 |
232033211330147 has 2 divisors, whose sum is σ = 232033211330148. Its totient is φ = 232033211330146.
The previous prime is 232033211330131. The next prime is 232033211330269. The reversal of 232033211330147 is 741033112330232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 232033211330147 - 24 = 232033211330131 is a prime.
It is a super-2 number, since 2×2320332113301472 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (232033211335147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116016605665073 + 116016605665074.
It is an arithmetic number, because the mean of its divisors is an integer number (116016605665074).
Almost surely, 2232033211330147 is an apocalyptic number.
232033211330147 is a deficient number, since it is larger than the sum of its proper divisors (1).
232033211330147 is an equidigital number, since it uses as much as digits as its factorization.
232033211330147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 232033211330147 its reverse (741033112330232), we get a palindrome (973066323660379).
The spelling of 232033211330147 in words is "two hundred thirty-two trillion, thirty-three billion, two hundred eleven million, three hundred thirty thousand, one hundred forty-seven".
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