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23205510431113 is a prime number
BaseRepresentation
bin1010100011010111101000…
…01101001100000110001001
310001011102110220212101000111
411101223310031030012021
511020144341132243423
6121204244143234321
74613354116100563
oct521536415140611
9101142426771014
1023205510431113
11743744674340a
1227294725a89a1
13cc436895961a
145a321d006333
152a39666ce60d
hex151af434c189

23205510431113 has 2 divisors, whose sum is σ = 23205510431114. Its totient is φ = 23205510431112.

The previous prime is 23205510431093. The next prime is 23205510431161. The reversal of 23205510431113 is 31113401550232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15871363596544 + 7334146834569 = 3983888^2 + 2708163^2 .

It is a cyclic number.

It is not a de Polignac number, because 23205510431113 - 29 = 23205510430601 is a prime.

It is a super-2 number, since 2×232055104311132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (23205510431713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11602755215556 + 11602755215557.

It is an arithmetic number, because the mean of its divisors is an integer number (11602755215557).

Almost surely, 223205510431113 is an apocalyptic number.

It is an amenable number.

23205510431113 is a deficient number, since it is larger than the sum of its proper divisors (1).

23205510431113 is an equidigital number, since it uses as much as digits as its factorization.

23205510431113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 23205510431113 its reverse (31113401550232), we get a palindrome (54318911981345).

The spelling of 23205510431113 in words is "twenty-three trillion, two hundred five billion, five hundred ten million, four hundred thirty-one thousand, one hundred thirteen".