Base | Representation |
---|---|
bin | 110100110001100000001011… |
… | …110101000011001101110001 |
3 | 1010102210120021011201201210101 |
4 | 310301200023311003031301 |
5 | 220410212233132211032 |
6 | 2141345212454432401 |
7 | 66613455045046633 |
oct | 6461401365031561 |
9 | 1112716234651711 |
10 | 232100231132017 |
11 | 67a551786a7186 |
12 | 220466b5962701 |
13 | 9c67c5b609521 |
14 | 41459d5488a53 |
15 | 1bc76d64d8de7 |
hex | d3180bd43371 |
232100231132017 has 2 divisors, whose sum is σ = 232100231132018. Its totient is φ = 232100231132016.
The previous prime is 232100231131969. The next prime is 232100231132027. The reversal of 232100231132017 is 710231132001232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129250431994896 + 102849799137121 = 11368836^2 + 10141489^2 .
It is a cyclic number.
It is not a de Polignac number, because 232100231132017 - 235 = 232065871393649 is a prime.
It is not a weakly prime, because it can be changed into another prime (232100231132027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116050115566008 + 116050115566009.
It is an arithmetic number, because the mean of its divisors is an integer number (116050115566009).
Almost surely, 2232100231132017 is an apocalyptic number.
It is an amenable number.
232100231132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
232100231132017 is an equidigital number, since it uses as much as digits as its factorization.
232100231132017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 232100231132017 its reverse (710231132001232), we get a palindrome (942331363133249).
The spelling of 232100231132017 in words is "two hundred thirty-two trillion, one hundred billion, two hundred thirty-one million, one hundred thirty-two thousand, seventeen".
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