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2321041164343 = 11219182158383
BaseRepresentation
bin100001110001101000110…
…101011000100000110111
322012220000100102202221021
4201301220311120200313
5301011443014224333
64534134355202011
7326455364243026
oct41615065304067
98186010382837
102321041164343
11815391256300
123159bbba6307
1313ab4768b585
14804a629c8bd
1540597a1a82d
hex21c68d58837

2321041164343 has 6 divisors (see below), whose sum is σ = 2551227065072. Its totient is φ = 2110037422020.

The previous prime is 2321041164341. The next prime is 2321041164353. The reversal of 2321041164343 is 3434611401232.

It is not a de Polignac number, because 2321041164343 - 21 = 2321041164341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2321041164299 and 2321041164308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2321041164341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 9591079071 + ... + 9591079312.

Almost surely, 22321041164343 is an apocalyptic number.

2321041164343 is a deficient number, since it is larger than the sum of its proper divisors (230185900729).

2321041164343 is a wasteful number, since it uses less digits than its factorization.

2321041164343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19182158405 (or 19182158394 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 2321041164343 its reverse (3434611401232), we get a palindrome (5755652565575).

The spelling of 2321041164343 in words is "two trillion, three hundred twenty-one billion, forty-one million, one hundred sixty-four thousand, three hundred forty-three".

Divisors: 1 11 121 19182158383 211003742213 2321041164343