Base | Representation |
---|---|
bin | 10101100111100010… |
… | …110101011010111001 |
3 | 2012220200111212022112 |
4 | 111213202311122321 |
5 | 340014234141213 |
6 | 14355150102105 |
7 | 1451133632606 |
oct | 254742653271 |
9 | 65820455275 |
10 | 23212021433 |
11 | 9931643297 |
12 | 45b97aa935 |
13 | 225bc95133 |
14 | 11a2b1d6ad |
15 | 90cc40ea8 |
hex | 5678b56b9 |
23212021433 has 2 divisors, whose sum is σ = 23212021434. Its totient is φ = 23212021432.
The previous prime is 23212021411. The next prime is 23212021439. The reversal of 23212021433 is 33412021232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19929533584 + 3282487849 = 141172^2 + 57293^2 .
It is a cyclic number.
It is not a de Polignac number, because 23212021433 - 214 = 23212005049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23212021399 and 23212021408.
It is not a weakly prime, because it can be changed into another prime (23212021439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606010716 + 11606010717.
It is an arithmetic number, because the mean of its divisors is an integer number (11606010717).
Almost surely, 223212021433 is an apocalyptic number.
It is an amenable number.
23212021433 is a deficient number, since it is larger than the sum of its proper divisors (1).
23212021433 is an equidigital number, since it uses as much as digits as its factorization.
23212021433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 23212021433 its reverse (33412021232), we get a palindrome (56624042665).
The spelling of 23212021433 in words is "twenty-three billion, two hundred twelve million, twenty-one thousand, four hundred thirty-three".
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