Base | Representation |
---|---|
bin | 1010100011100011110011… |
… | …00110001011101101000111 |
3 | 10001012001100012122112000011 |
4 | 11101301321212023231013 |
5 | 11020301231042221020 |
6 | 121211244313531051 |
7 | 4614005033533345 |
oct | 521617146135507 |
9 | 101161305575004 |
10 | 23212043320135 |
11 | 743a19935464a |
12 | 272a796413a87 |
13 | cc4b6a254427 |
14 | 5a367c8cc995 |
15 | 2a3be9eca35a |
hex | 151c7998bb47 |
23212043320135 has 16 divisors (see below), whose sum is σ = 27875235840480. Its totient is φ = 18555780309120.
The previous prime is 23212043320111. The next prime is 23212043320153. The reversal of 23212043320135 is 53102334021232.
It is not a de Polignac number, because 23212043320135 - 27 = 23212043320007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23212043320097 and 23212043320106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 132542889 + ... + 132717901.
It is an arithmetic number, because the mean of its divisors is an integer number (1742202240030).
Almost surely, 223212043320135 is an apocalyptic number.
23212043320135 is a deficient number, since it is larger than the sum of its proper divisors (4663192520345).
23212043320135 is a wasteful number, since it uses less digits than its factorization.
23212043320135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 194658.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 23212043320135 its reverse (53102334021232), we get a palindrome (76314377341367).
The spelling of 23212043320135 in words is "twenty-three trillion, two hundred twelve billion, forty-three million, three hundred twenty thousand, one hundred thirty-five".
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