Base | Representation |
---|---|
bin | 1010100011100011110011… |
… | …00110001011101101011001 |
3 | 10001012001100012122112000211 |
4 | 11101301321212023231121 |
5 | 11020301231042221103 |
6 | 121211244313531121 |
7 | 4614005033533402 |
oct | 521617146135531 |
9 | 101161305575024 |
10 | 23212043320153 |
11 | 743a199354666 |
12 | 272a796413aa1 |
13 | cc4b6a25443c |
14 | 5a367c8cc9a9 |
15 | 2a3be9eca36d |
hex | 151c7998bb59 |
23212043320153 has 2 divisors, whose sum is σ = 23212043320154. Its totient is φ = 23212043320152.
The previous prime is 23212043320111. The next prime is 23212043320171. The reversal of 23212043320153 is 35102334021232.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14963613368089 + 8248429952064 = 3868283^2 + 2872008^2 .
It is a cyclic number.
It is not a de Polignac number, because 23212043320153 - 233 = 23203453385561 is a prime.
It is not a weakly prime, because it can be changed into another prime (23212043320183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606021660076 + 11606021660077.
It is an arithmetic number, because the mean of its divisors is an integer number (11606021660077).
Almost surely, 223212043320153 is an apocalyptic number.
It is an amenable number.
23212043320153 is a deficient number, since it is larger than the sum of its proper divisors (1).
23212043320153 is an equidigital number, since it uses as much as digits as its factorization.
23212043320153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 23212043320153 its reverse (35102334021232), we get a palindrome (58314377341385).
The spelling of 23212043320153 in words is "twenty-three trillion, two hundred twelve billion, forty-three million, three hundred twenty thousand, one hundred fifty-three".
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