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23212043320153 is a prime number
BaseRepresentation
bin1010100011100011110011…
…00110001011101101011001
310001012001100012122112000211
411101301321212023231121
511020301231042221103
6121211244313531121
74614005033533402
oct521617146135531
9101161305575024
1023212043320153
11743a199354666
12272a796413aa1
13cc4b6a25443c
145a367c8cc9a9
152a3be9eca36d
hex151c7998bb59

23212043320153 has 2 divisors, whose sum is σ = 23212043320154. Its totient is φ = 23212043320152.

The previous prime is 23212043320111. The next prime is 23212043320171. The reversal of 23212043320153 is 35102334021232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14963613368089 + 8248429952064 = 3868283^2 + 2872008^2 .

It is a cyclic number.

It is not a de Polignac number, because 23212043320153 - 233 = 23203453385561 is a prime.

It is not a weakly prime, because it can be changed into another prime (23212043320183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606021660076 + 11606021660077.

It is an arithmetic number, because the mean of its divisors is an integer number (11606021660077).

Almost surely, 223212043320153 is an apocalyptic number.

It is an amenable number.

23212043320153 is a deficient number, since it is larger than the sum of its proper divisors (1).

23212043320153 is an equidigital number, since it uses as much as digits as its factorization.

23212043320153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 23212043320153 its reverse (35102334021232), we get a palindrome (58314377341385).

The spelling of 23212043320153 in words is "twenty-three trillion, two hundred twelve billion, forty-three million, three hundred twenty thousand, one hundred fifty-three".