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232121111113 is a prime number
BaseRepresentation
bin1101100000101101111…
…1110001001001001001
3211012010220211012022101
43120023133301021021
512300341001023423
6254345052553401
722525114614163
oct3301337611111
9735126735271
10232121111113
118a495352421
1238ba0a82861
1318b72c841b8
14b34010d933
1560883d57ad
hex360b7f1249

232121111113 has 2 divisors, whose sum is σ = 232121111114. Its totient is φ = 232121111112.

The previous prime is 232121111081. The next prime is 232121111143. The reversal of 232121111113 is 311111121232.

232121111113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218156253184 + 13964857929 = 467072^2 + 118173^2 .

It is a cyclic number.

It is not a de Polignac number, because 232121111113 - 25 = 232121111081 is a prime.

It is not a weakly prime, because it can be changed into another prime (232121111143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116060555556 + 116060555557.

It is an arithmetic number, because the mean of its divisors is an integer number (116060555557).

Almost surely, 2232121111113 is an apocalyptic number.

It is an amenable number.

232121111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

232121111113 is an equidigital number, since it uses as much as digits as its factorization.

232121111113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 19.

Adding to 232121111113 its reverse (311111121232), we get a palindrome (543232232345).

The spelling of 232121111113 in words is "two hundred thirty-two billion, one hundred twenty-one million, one hundred eleven thousand, one hundred thirteen".