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232125433 = 4722721757
BaseRepresentation
bin11011101010111…
…11001111111001
3121011210012020021
431311133033321
5433411003213
635011130441
75516014351
oct1565371771
9534705207
10232125433
1110a035301
12658a3a21
1339124837
1422b85b61
15155a2d8d
hexdd5f3f9

232125433 has 8 divisors (see below), whose sum is σ = 238119552. Its totient is φ = 226175376.

The previous prime is 232125409. The next prime is 232125437. The reversal of 232125433 is 334521232.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 232125433 - 217 = 231994361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 232125398 and 232125407.

It is not an unprimeable number, because it can be changed into a prime (232125437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 210 + ... + 21547.

It is an arithmetic number, because the mean of its divisors is an integer number (29764944).

Almost surely, 2232125433 is an apocalyptic number.

It is an amenable number.

232125433 is a deficient number, since it is larger than the sum of its proper divisors (5994119).

232125433 is a wasteful number, since it uses less digits than its factorization.

232125433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22031.

The product of its digits is 4320, while the sum is 25.

The square root of 232125433 is about 15235.6631952797. The cubic root of 232125433 is about 614.5740836676.

Adding to 232125433 its reverse (334521232), we get a palindrome (566646665).

The spelling of 232125433 in words is "two hundred thirty-two million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 47 227 10669 21757 1022579 4938839 232125433