Base | Representation |
---|---|
bin | 110100110011000001110000… |
… | …101111100100111010111011 |
3 | 1010110011120200221020222021101 |
4 | 310303001300233210322323 |
5 | 220413421321333124011 |
6 | 2141505301140152231 |
7 | 66624154310531422 |
oct | 6463016057447273 |
9 | 1113146627228241 |
10 | 232205003411131 |
11 | 67a95652943203 |
12 | 22062a75998677 |
13 | 9c74ab7a35a5a |
14 | 414aad42502b9 |
15 | 1bca2b96972c1 |
hex | d33070be4ebb |
232205003411131 has 2 divisors, whose sum is σ = 232205003411132. Its totient is φ = 232205003411130.
The previous prime is 232205003411119. The next prime is 232205003411141. The reversal of 232205003411131 is 131114300502232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232205003411131 - 211 = 232205003409083 is a prime.
It is a super-2 number, since 2×2322050034111312 (a number of 30 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 232205003411131.
It is not a weakly prime, because it can be changed into another prime (232205003411141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116102501705565 + 116102501705566.
It is an arithmetic number, because the mean of its divisors is an integer number (116102501705566).
Almost surely, 2232205003411131 is an apocalyptic number.
232205003411131 is a deficient number, since it is larger than the sum of its proper divisors (1).
232205003411131 is an equidigital number, since it uses as much as digits as its factorization.
232205003411131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 232205003411131 its reverse (131114300502232), we get a palindrome (363319303913363).
The spelling of 232205003411131 in words is "two hundred thirty-two trillion, two hundred five billion, three million, four hundred eleven thousand, one hundred thirty-one".
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