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23223100444433 is a prime number
BaseRepresentation
bin1010100011111000011001…
…01001110000111100010001
310001020002212210120122001022
411101330030221300330101
511020441402203210213
6121220313422245225
74614546035535341
oct521741451607421
9101202783518038
1023223100444433
1174439528597aa
122730961426815
13cc5c0cc5cb26
145a400b1ccd21
152a4145aa0308
hex151f0ca70f11

23223100444433 has 2 divisors, whose sum is σ = 23223100444434. Its totient is φ = 23223100444432.

The previous prime is 23223100444393. The next prime is 23223100444441. The reversal of 23223100444433 is 33444400132232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23025957340369 + 197143104064 = 4798537^2 + 444008^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23223100444433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23223100444393 and 23223100444402.

It is not a weakly prime, because it can be changed into another prime (23223100444133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11611550222216 + 11611550222217.

It is an arithmetic number, because the mean of its divisors is an integer number (11611550222217).

Almost surely, 223223100444433 is an apocalyptic number.

It is an amenable number.

23223100444433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23223100444433 is an equidigital number, since it uses as much as digits as its factorization.

23223100444433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 23223100444433 its reverse (33444400132232), we get a palindrome (56667500576665).

The spelling of 23223100444433 in words is "twenty-three trillion, two hundred twenty-three billion, one hundred million, four hundred forty-four thousand, four hundred thirty-three".