Base | Representation |
---|---|
bin | 110100110100011110011011… |
… | …110111011010101100010011 |
3 | 1010110112002112210121001220122 |
4 | 310310132123313122230103 |
5 | 220422034114322300413 |
6 | 2142023115200100455 |
7 | 66634306226321144 |
oct | 6464363367325423 |
9 | 1113462483531818 |
10 | 232304511134483 |
11 | 680238764075a7 |
12 | 2207a20690472b |
13 | 9c812b5565928 |
14 | 4151853b69acb |
15 | 1bccb90592108 |
hex | d3479bddab13 |
232304511134483 has 2 divisors, whose sum is σ = 232304511134484. Its totient is φ = 232304511134482.
The previous prime is 232304511134411. The next prime is 232304511134497. The reversal of 232304511134483 is 384431115403232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232304511134483 - 230 = 232303437392659 is a prime.
It is a super-2 number, since 2×2323045111344832 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (232304511134183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116152255567241 + 116152255567242.
It is an arithmetic number, because the mean of its divisors is an integer number (116152255567242).
Almost surely, 2232304511134483 is an apocalyptic number.
232304511134483 is a deficient number, since it is larger than the sum of its proper divisors (1).
232304511134483 is an equidigital number, since it uses as much as digits as its factorization.
232304511134483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 829440, while the sum is 44.
The spelling of 232304511134483 in words is "two hundred thirty-two trillion, three hundred four billion, five hundred eleven million, one hundred thirty-four thousand, four hundred eighty-three".
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