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2323214401913 is a prime number
BaseRepresentation
bin100001110011101010010…
…111101000000101111001
322020002121210202200102122
4201303222113220011321
5301030420341330123
64535134151211025
7326563263406436
oct41635227500571
98202553680378
102323214401913
118162a6a66909
12316307976a75
1313b1029ac772
1480630b70b8d
15406736ecbc8
hex21cea5e8179

2323214401913 has 2 divisors, whose sum is σ = 2323214401914. Its totient is φ = 2323214401912.

The previous prime is 2323214401903. The next prime is 2323214401919. The reversal of 2323214401913 is 3191044123232.

2323214401913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1753209031744 + 570005370169 = 1324088^2 + 754987^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2323214401913 is a prime.

It is a super-3 number, since 3×23232144019133 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2323214401919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1161607200956 + 1161607200957.

It is an arithmetic number, because the mean of its divisors is an integer number (1161607200957).

Almost surely, 22323214401913 is an apocalyptic number.

It is an amenable number.

2323214401913 is a deficient number, since it is larger than the sum of its proper divisors (1).

2323214401913 is an equidigital number, since it uses as much as digits as its factorization.

2323214401913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 2323214401913 in words is "two trillion, three hundred twenty-three billion, two hundred fourteen million, four hundred one thousand, nine hundred thirteen".