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23234035411049 is a prime number
BaseRepresentation
bin1010100100001100110000…
…11011010110100001101001
310001021011002212122111020212
411102012120123112201221
511021131301031123144
6121225322444430505
74615414025321441
oct522063033264151
9101234085574225
1023234035411049
117448554308aa1
122732ab3548435
13cc6c63567488
145a47675b1121
152a4585a9549e
hex1521986d6869

23234035411049 has 2 divisors, whose sum is σ = 23234035411050. Its totient is φ = 23234035411048.

The previous prime is 23234035411031. The next prime is 23234035411121. The reversal of 23234035411049 is 94011453043232.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17521423939600 + 5712611471449 = 4185860^2 + 2390107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23234035411049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23234035410997 and 23234035411015.

It is not a weakly prime, because it can be changed into another prime (23234035411949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11617017705524 + 11617017705525.

It is an arithmetic number, because the mean of its divisors is an integer number (11617017705525).

Almost surely, 223234035411049 is an apocalyptic number.

It is an amenable number.

23234035411049 is a deficient number, since it is larger than the sum of its proper divisors (1).

23234035411049 is an equidigital number, since it uses as much as digits as its factorization.

23234035411049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 23234035411049 in words is "twenty-three trillion, two hundred thirty-four billion, thirty-five million, four hundred eleven thousand, forty-nine".