Base | Representation |
---|---|
bin | 110100110101000000011100… |
… | …110100010110110101100011 |
3 | 1010110122120211011102201022221 |
4 | 310311000130310112311203 |
5 | 220423133414242101431 |
6 | 2142051555255011511 |
7 | 66640041265345111 |
oct | 6465003464266543 |
9 | 1113576734381287 |
10 | 232341034331491 |
11 | 68038308842038 |
12 | 220852ba369b97 |
13 | 9c848862111c7 |
14 | 415351a696ab1 |
15 | 1bcdacbc00111 |
hex | d3501cd16d63 |
232341034331491 has 2 divisors, whose sum is σ = 232341034331492. Its totient is φ = 232341034331490.
The previous prime is 232341034331383. The next prime is 232341034331501. The reversal of 232341034331491 is 194133430143232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232341034331491 - 231 = 232338886847843 is a prime.
It is a super-3 number, since 3×2323410343314913 (a number of 44 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (232341034331191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116170517165745 + 116170517165746.
It is an arithmetic number, because the mean of its divisors is an integer number (116170517165746).
Almost surely, 2232341034331491 is an apocalyptic number.
232341034331491 is a deficient number, since it is larger than the sum of its proper divisors (1).
232341034331491 is an equidigital number, since it uses as much as digits as its factorization.
232341034331491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 559872, while the sum is 43.
The spelling of 232341034331491 in words is "two hundred thirty-two trillion, three hundred forty-one billion, thirty-four million, three hundred thirty-one thousand, four hundred ninety-one".
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