Base | Representation |
---|---|
bin | 1010100100011010010101… |
… | …01101001111000111100001 |
3 | 10001021211220122112122021102 |
4 | 11102031022231033013201 |
5 | 11021241211240123131 |
6 | 121232525441004145 |
7 | 4616062416311066 |
oct | 522151255170741 |
9 | 101254818478242 |
10 | 23241321411041 |
11 | 7450653044698 |
12 | 27343a7623655 |
13 | cc7854ba8a86 |
14 | 5a4c590d8c6d |
15 | 2a48605551cb |
hex | 15234ab4f1e1 |
23241321411041 has 2 divisors, whose sum is σ = 23241321411042. Its totient is φ = 23241321411040.
The previous prime is 23241321411037. The next prime is 23241321411073. The reversal of 23241321411041 is 14011412314232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22675967801041 + 565353610000 = 4761929^2 + 751900^2 .
It is a cyclic number.
It is not a de Polignac number, because 23241321411041 - 22 = 23241321411037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23241321410995 and 23241321411013.
It is not a weakly prime, because it can be changed into another prime (23241321411241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11620660705520 + 11620660705521.
It is an arithmetic number, because the mean of its divisors is an integer number (11620660705521).
Almost surely, 223241321411041 is an apocalyptic number.
It is an amenable number.
23241321411041 is a deficient number, since it is larger than the sum of its proper divisors (1).
23241321411041 is an equidigital number, since it uses as much as digits as its factorization.
23241321411041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 23241321411041 its reverse (14011412314232), we get a palindrome (37252733725273).
The spelling of 23241321411041 in words is "twenty-three trillion, two hundred forty-one billion, three hundred twenty-one million, four hundred eleven thousand, forty-one".
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