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23241421999753 is a prime number
BaseRepresentation
bin1010100100011010100001…
…01100111100111010001001
310001021212011122211002001021
411102031100230330322021
511021241413012443003
6121232543432552441
74616065050304456
oct522152054747211
9101255148732037
1023241421999753
1174506a48a8461
122734415252721
13cc786c997519
145a4c6860082d
152a48692c42bd
hex152350b3ce89

23241421999753 has 2 divisors, whose sum is σ = 23241421999754. Its totient is φ = 23241421999752.

The previous prime is 23241421999619. The next prime is 23241421999793. The reversal of 23241421999753 is 35799912414232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23063074574409 + 178347425344 = 4802403^2 + 422312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23241421999753 is a prime.

It is a super-2 number, since 2×232414219997532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23241421999691 and 23241421999700.

It is not a weakly prime, because it can be changed into another prime (23241421999793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11620710999876 + 11620710999877.

It is an arithmetic number, because the mean of its divisors is an integer number (11620710999877).

Almost surely, 223241421999753 is an apocalyptic number.

It is an amenable number.

23241421999753 is a deficient number, since it is larger than the sum of its proper divisors (1).

23241421999753 is an equidigital number, since it uses as much as digits as its factorization.

23241421999753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29393280, while the sum is 61.

The spelling of 23241421999753 in words is "twenty-three trillion, two hundred forty-one billion, four hundred twenty-one million, nine hundred ninety-nine thousand, seven hundred fifty-three".