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2325200055 = 351019152123
BaseRepresentation
bin1000101010010111…
…1011110010110111
320000001021101211120
42022211323302313
514230222400210
61022421035023
7111422605623
oct21245736267
96001241746
102325200055
11a93573242
1254a855a73
132b0959429
14180b4c183
15d91ed270
hex8a97bcb7

2325200055 has 16 divisors (see below), whose sum is σ = 3723995520. Its totient is φ = 1238881568.

The previous prime is 2325200039. The next prime is 2325200063. The reversal of 2325200055 is 5500025232.

It is a cyclic number.

It is not a de Polignac number, because 2325200055 - 24 = 2325200039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2325199998 and 2325200034.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60777 + ... + 91346.

It is an arithmetic number, because the mean of its divisors is an integer number (232749720).

Almost surely, 22325200055 is an apocalyptic number.

2325200055 is a deficient number, since it is larger than the sum of its proper divisors (1398795465).

2325200055 is a wasteful number, since it uses less digits than its factorization.

2325200055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153150.

The product of its (nonzero) digits is 3000, while the sum is 24.

The square root of 2325200055 is about 48220.3282340550. The cubic root of 2325200055 is about 1324.8095238238.

Adding to 2325200055 its reverse (5500025232), we get a palindrome (7825225287).

The spelling of 2325200055 in words is "two billion, three hundred twenty-five million, two hundred thousand, fifty-five".

Divisors: 1 3 5 15 1019 3057 5095 15285 152123 456369 760615 2281845 155013337 465040011 775066685 2325200055